| Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|
| 29725 | 惠子铭 | 级数求和 | C++ | Accepted | 0 MS | 196 KB | 385 | 2023-11-02 18:54:23 |
#include <stdio.h> #include <stdlib.h> int main() { int n, k; double s; scanf("%d", &k); s = 0.0; n = 1; while (1) //死循环 { s = s + 1.0/n; //求s=1+1/2+...+1/n if(s > k) { printf("%d\n", n); break; //跳出死循环 } n++; } return 0; }