Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|
31317 | lnx | 求小数的某一位 | C++ | Accepted | 0 MS | 252 KB | 209 | 2023-11-18 13:08:53 |
#include<iostream> #include<cmath> using namespace std; int main() { int a,b,n; cin>>a>>b>>n; double k=a*1.0/b; int m=(int) (k*pow(10,n)); //cout<<m<<endl; int t=m%10; cout<<t; return 0; }