Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|
32764 | lnx | 最大值和最小值的差 | C++ | Accepted | 0 MS | 240 KB | 264 | 2023-12-02 19:32:46 |
#include<iostream> #include<cmath> using namespace std; int main() { int n; cin>>n; int a[n+1]; int m=-10000,k=10000; for(int i=1;i<=n;i++) cin>>a[i]; for(int i=1;i<=n;i++) { m=max(m,a[i]); k=min(k,a[i]); } cout<<m-k; return 0; }