Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|
4973 | 盛梓恒_cat | [在线测评解答教程] 求和 | C | Accepted | 0 MS | 192 KB | 126 | 2023-01-13 14:02:18 |
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }