| Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|
| 67313 | jdf25_wangchs | [在线测评解答教程] 求和 | C | Accepted | 0 MS | 196 KB | 130 | 2025-09-10 17:19:18 |
#include<stdio.h> int main() { int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }