提交时间:2026-06-06 12:58:52

运行 ID: 90555

#include <iostream> using namespace std; int main() { string k,c; cin>>k>>c; for (int i=0;i<c.length();i++) { int t=(k[i%k.length()]&31)-1; c[i]=(c[i]&31)-t>0?c[i]-t:c[i]-t+26; } cout<<c<<endl; return 0; }